I am introduced to ancilla qubits which are usually initialized to $\vert 0 \rangle$. It seems that an ancilla qubit is equivalent to the $0$ bit in classical computing as it will evaluate to $\vert 0 \rangle$ 100% of the time. My question is that can I conclude any qubit will always be in superposition regardless of the probabilities of $\alpha$ and $\beta$ since $\vert 0 \rangle + 0\vert 1 \rangle = \vert 0 \rangle$ and $0\vert 0 \rangle + \vert 1 \rangle = \vert 1 \rangle$? How about physically, are qubits prepared according to some procedure that differ if it will be initialized to $\vert 0 \rangle$ or $\vert 1 \rangle$ or in superposition?
Edit: this is a related comment but it doesn't answer my question regarding if the process of physically preparing qubits different from non-entangled qubits vs entangled ones.