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Possible Duplicate:

Get a “step by step” evaluation in Mathematica

I have a list of inequalities combined with quantifiers. And *Mathematica* is able to reduce to simple statement with the `Reduce[]`

command , is it possible to see how it comes up with it.

```
Reduce[Exists[{p, \[Eta], \[Theta]}, \[Eta] (p - 1) < 1/
2 && \[Lambda] p < 2 && (1 - \[Lambda]) p/(p - 1) <
e && \[Theta] (1 - \[Lambda]) p/(p - 1) < 1/2 + \[Eta] &&
0 < \[Lambda] < 1 && 1 < p &&
e > 0 && \[Theta] >
0 && ((1/2 - \[Eta]) (1 + 1/(e - (1 - \[Lambda]) p/(p - 1))) <
1 || (1/2 - \[Eta]) (1 +
1/(e - (1 - \[Lambda]) p/(p -
1))) < \[Theta] e)], {\[Lambda], e}, Reals]
```

Thanks!

1

Probably not... possible dupe: http://mathematica.stackexchange.com/q/148/5

– rm -rf – 2012-10-30T18:47:19.227The link just considers step by step evaluation of differentiation. This is different. – warsaga – 2012-10-30T19:10:29.833

1Did you read the answers further below that tell you to use

`WolframAlpha[]`

? – rm -rf – 2012-10-30T19:17:31.390Simply put: no, don't count on

Mathematicato tell you what it does, step by step, in general. Wolfram Alpha will do it for you, but that's a different kettle of fish. – J. M.'s ennui – 2012-10-30T21:59:36.593@J.M. From the etymologist inside: http://www.phrases.org.uk/meanings/kettle-of-fish.html

– Dr. belisarius – 2012-10-31T03:27:38.830