How can I check the hash of a bitcoin block?

2

1

Let's pick an example bitcoin block: #499583

This is the block: https://insight.bitpay.com/api/rawblock/000000000000000000677c4077da7c9f01dde5f332ba2fbff962ee699714d5da

It starts with 00000020164a1e4a7f34b96b0e201d....

I'm trying to hash it so that the hash is 000000000000000000677c4077da7c9f01dde5f332ba2fbff962ee699714d5da again. This is my Javascript-Code:

var Bitcoin = require('bitcoinjs-lib');
var request = require('request');
var crypto = require('crypto');

function getRawBlock(blockHash) {
  return new Promise((resolve, reject) => {
    request('https://insight.bitpay.com/api/rawblock/' + blockHash, // hitting an insight API to get the full block
      (error, response, body) => {
        try {
          var block = JSON.parse(body); // result is in JSON
          resolve(block.rawblock)
        } catch (error) {
          reject(error)
        }
      })
  })
}

getRawBlock('000000000000000000677c4077da7c9f01dde5f332ba2fbff962ee699714d5da')
  .then((rawBlock) => {
    var hash = crypto.createHash('sha256').update(rawBlock).digest('hex');
     console.log(hash);
  })
})

But the result is 484cd10be70dbc7615dd9a71b1f91375b100715d9b2a0ecc6a05b9d247a8cda9. What am I doing wrong? The result should be 000000000000000000677c4077da7c9f01dde5f332ba2fbff962ee699714d5da. Do I hash something in the wrong format?

ndsvw

Posted 2017-12-16T11:12:06.683

Reputation: 1 997

Answers

4

Seems to me that you are hashing the whole block instead of header only. Take my code (in C++).

void test ( )
{
  const MyByteArray header ( QByteArray::fromHex (
     "00000020" // version
     "164a1e4a7f34b96b0e201dcc6a623c63fe3874696e4875000000000000000000" // prev hash
     "49de8b4f4bfa9fc890d3d28a93156a111f891dc680090cd497b58a7d5c2b09cf" // merkle
     "2f62345a"      // timestamp
     "edb00018"      // bits
     "ffdfd257" ) ); // nonce
  const MyKey32 key ( header.sha256d ( ) );
  qDebug ( ) << key.toString ( );
}

and the output is:

000000000000000000677c4077da7c9f01dde5f332ba2fbff962ee699714d5da

amaclin

Posted 2017-12-16T11:12:06.683

Reputation: 6 140

What format does the input data need to be? I'm trying to manually plug the data into a sha256 calculator, and not getting the correct result. I know it is a double sha256 but I must be making a mistake somewhere – chytrik – 2017-12-16T21:23:42.893

input is raw binary data 80 bytes length – amaclin – 2017-12-17T04:48:10.027

I thank you amaclin, I did not know that you only need to hash the header. But can someone maybe write such a short program in Javascript or Java or Python? (I can't read C++, I don't know what a QByteArray ist, what MyKey32 ist, what the proramm is really doing.) – ndsvw – 2017-12-17T07:58:43.700

1

#include <openssl/sha.h>

int main()
{
    const char * sin = "00000020" // version
        "164a1e4a7f34b96b0e201dcc6a623c63fe3874696e4875000000000000000000" // prev hash
        "49de8b4f4bfa9fc890d3d28a93156a111f891dc680090cd497b58a7d5c2b09cf" // merkle
        "2f62345a"      // timestamp
        "edb00018"      // bits
        "ffdfd257";
    string xxs = Helper::decode16(sin);

    unsigned char md[32];
    SHA256_CTX ctx;
    SHA256_Init(&ctx);
    SHA256_Update(&ctx, xxs.data(), xxs.length());
    SHA256_Final(md, &ctx);

    SHA256_Init(&ctx);
    SHA256_Update(&ctx, md, 32);
    SHA256_Final(md, &ctx);

    const char * tbl = "0123456789abcdef";
    char outs[64 + 1] = { 0 };
    for (int i = 0; i < 32; ++i)
    {
        outs[2 * i + 0] = tbl[md[31-i] >> 4];
        outs[2 * i + 1] = tbl[md[31 - i] & 0xf];
    }
    printf("%s\n", outs);

    return 0;
}

my code uses openssl. passed.

swigger

Posted 2017-12-16T11:12:06.683

Reputation: 11