Romanian general election, 1928
General elections were held in Romania in December 1928. The Chamber of Deputies was elected on 12 December, whilst the Senate was elected in three stages on 15, 17 and 19 December. The result was a victory for the governing National Peasants' Party-led alliance, which won 348 of the 387 seats in the Chamber of Deputies and 105 of the 110 seats in the Senate elected through universal male vote. Of the 348 Chamber seats won by the alliance, the National Peasants' Party won 326, the Social Democratic Party won 9, the German Party won 8, the Hungarian People's Party won 2 and three were won by Jewish candidates. It is generally regarded as the freest election ever held in Romania until the 1990s.
|National Peasants' Party-led alliance||2,208,922||79.2||348||+294||105||+88|
|National Liberal Party||185,939||6.7||13||–305||0||–92|
|National Party–People's Party||70,790||2.5||5||+5||0||0|
|Peasant Workers' Bloc||38,851||1.4||0||New||0||New|
|National-Christian Defense League||32,273||1.2||0||New||0||New|
|Source: Nohlen & Stöver|